Bismarck.Bloodbeat said:
Bismarck.Cuelebra said:
Bismarck.Bloodbeat said:
Bismarck.Cuelebra said:
Bismarck.Bloodbeat said:
Leviathan.Hohenheim said:
Hi guys ;o I haven't posted in like 30 pages!
I ate 1600 calories worth of candy just now. It's not helping me get into a hot, buff body.
But it was so worth it.
Though I feel kind of sick now :<
Or how about you put your sweets into a giant block of ice. By the time you've worked through it with a pickaxe, you'll have burned them off. ;)
Wouldnt work. diffusion would cause sugar molecules to move into the ice. lol so ud be eatting sugar while chewing through the ice
Really? I wouldn't have thought sucrose would have much mobility at lower temperatures through solid ice. :P
Well yes and no. If you can come up with a way to transport the candy directly into the ice block while its still frozen then yes. Sucrose diffusion rate would decrease because of temperature.
Assuming u place in the candy into a mass of water and allow it to freeze over time is was what i was imagining.
Additionally because of the polar charges of H20. Mobility via diffusion is not completely reduced to 0. H20 polar composition actually turns into a honey comb formation while frozen. allowing Van Der Walls to NOT be a factor in diffusion inhibition.
Your text to link here...
Assuming it wasn't hydrophobic. Try putting a skittle in ethanol and you'll see what I mean ;)
This is way too biochemistry-esque for a joke. Lol
lol its neither. hydrophobicity isnt factor on most sugars usually particular because they are in a class of chemicals known as hydrocarbons. The greater the length of the CH3 chain the less overall charge it posesses. Hense why most hydrocarbons are liquids or gases at room temp. For the fact that their charge is nearly insignificant in ionic/polar charged systems. e.g. water.
Ethanol when mixed with water is a completely different matter. as its not in the same class of hydrocarbons. Ethanol posses a hydroxyl substituent. The hydroxyl substituent does possesses a delta charge similar to that of water. however it again it is reduced by the overall length of the CH3 chain.
Therefor in organic chemistry we uses this to represent the reaction between H20 and EtOh
EtOH---OH2(l) + 2H20...(l) <-- ------->>EtOH(l) + 3H20...
the extended arrow and length represents that equilibrium would automically favor ethanol as an near inert compound vers a polar compound of EthOH---OH2.
Additionally, H20 polarity would not play a factor because of the fact that in solid state h20 molecules form a crystilline structure. the polar+ charge of the ...0-H-o-H-O-H... e.g. would always take precident because the delta charge of O- and the delta charge of H+ absolute values exceed the delta charge of the hydrocarbon in this case sucrose.